(4y^2)+8y+12x-20=0

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Solution for (4y^2)+8y+12x-20=0 equation: 


Simplifying
(4y2) + 8y + 12x + -20 = 0

Reorder the terms:
-20 + 12x + 8y + (4y2) = 0

Solving
-20 + 12x + 8y + (4y2) = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '20' to each side of the equation.
-20 + 12x + 8y + 20 + (4y2) = 0 + 20

Reorder the terms:
-20 + 20 + 12x + 8y + (4y2) = 0 + 20

Combine like terms: -20 + 20 = 0
0 + 12x + 8y + (4y2) = 0 + 20
12x + 8y + (4y2) = 0 + 20

Combine like terms: 0 + 20 = 20
12x + 8y + (4y2) = 20

Add '-8y' to each side of the equation.
12x + 8y + -8y + (4y2) = 20 + -8y

Combine like terms: 8y + -8y = 0
12x + 0 + (4y2) = 20 + -8y
12x + (4y2) = 20 + -8y

Add '(-4y2)' to each side of the equation.
12x + (4y2) + (-4y2) = 20 + -8y + (-4y2)

Combine like terms: (4y2) + (-4y2) = 0
12x + 0 = 20 + -8y + (-4y2)
12x = 20 + -8y + (-4y2)

Divide each side by '12'.
x = 1.666666667 + -0.6666666667y + (-0.3333333333y2)

Simplifying
x = 1.666666667 + -0.6666666667y + (-0.3333333333y2)

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